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(-2)^3(-x-4)-2-3^2=-2(x-4)-x
We move all terms to the left:
(-2)^3(-x-4)-2-3^2-(-2(x-4)-x)=0
We add all the numbers together, and all the variables
(-2)^3(-1x-4)-(-2(x-4)-x)-2-3^2=0
We add all the numbers together, and all the variables
(-2)^3(-1x-4)-(-2(x-4)-x)-11=0
We calculate terms in parentheses: -(-2(x-4)-x), so:We get rid of parentheses
-2(x-4)-x
We add all the numbers together, and all the variables
-1x-2(x-4)
We multiply parentheses
-1x-2x+8
We add all the numbers together, and all the variables
-3x+8
Back to the equation:
-(-3x+8)
(-2)^3(-1x-4)+3x-8-11=0
We add all the numbers together, and all the variables
3x+(-2)^3(-1x-4)-19=0
We move all terms containing x to the left, all other terms to the right
3x+(-2)^3(-1x-4)=19
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